Find the radius of the circle whose centre is (3,2) and passes through (-5,6)
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centre = c(3,2) passes through point = p(-5, 6)
- Distance Formula
d(c, p) = radius of circle
d(c, p) = √ ( (x2 - x1 )² + (y2 - y1)² )
= √ ( (-5 - 3)² + (6 - 2)² )
= √ ( (-8)² + (4)² )
= √ (64 + 16) = √80 = 4√5
= 4√5 = 8.92 unit
The radius of circle is 4√5 unit ir 8.92 unit.
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