Question

find the radius of the circle whose end points of the diameter is (24,1) and (2,23)

Answer 1

Let O is centre of circle.

Given

AB is diameter.

Then, OA = OB (Radius of Circle )

By Using Section Formula,

Coord. Of point O = { 26/2 , 24/2 }

= (13 ,12 )

Now, Radius OA = 11 Root 2.

[Find it by using Distance Formula ...

{Between OA or You can also find by

OB } ]

Hence, Radius of circle is 11 root 2 or 15.51 .

Answer 2

The “radius of the circle” is 15.55

Given:

The diameter are (24, 1), (2, 23)

To find:

Find the circle radius?

Answer:

End points of diameter are (24, 1) & (2, 23)

The distance between two points is $AB=\sqrt { ({ x }_{ 2 }-{ x }_{ 1 })^{ 2 }+({ y }_{ 2 }-{ y }_{ 1 })^{ 2 } }$

Assume (x,y) are the co-ordinates of the diameter

$AB\quad =\quad \sqrt { (2-24)^{ 2 }+(23-1)^{ 2 } }$

$AB=\sqrt{(-22)^{2}+(22)^{2}}$

$AB\quad =\quad \sqrt { (-22)^{ 2 }+(22)^{ 2 } }$

$AB\quad =\quad \sqrt { 484+484 }$

$AB\quad =\quad \sqrt { 968 }$

AB = 31.11

Radius of circle $=\frac{AB}{2}$

$=\frac{31.11}{2}$

The radius of the circle = 15.55