Question

Find the radius of the incircle of the regular hexagon of side 24 cm

Answer 1

area of regular hexagon is 6*root3/4a^2
area of equivi triangle=root3/4a^2
=root3/4*24
=root3*6
=6root3

Answer 2

Answer: Radius of the incircle would be 8√3 cm.

Step-by-step explanation:

Since we have given that

Side of hexagon = 24 cm

So, Radius of incircle would be

$\dfrac{\text{Area of hexagon}}{\text{Semi perimeter of hexagon}}\\\\=\dfrac{\dfrac{\sqrt{3}}{4}a^2}{\dfrac{6\times 24}{2}}\\\\=\dfrac{2\sqrt{3}\times 24\times 24}{6\times 24}\\\\=8\sqrt{3}$

Hence, radius of the incircle would be 8√3 cm.