Math, asked by aksyrt, 11 months ago

find the radius of the y²=4ax at (x,y)

Answers

Answered by Rajeshkumare
0
\left[y _{1}\right] = \left[ \left( -2\right) \,\sqrt{ax}\right][y​1​​]=[(−2)√​ax​​​] Algebra equation functional value

aksyrt: teri .......
Rajeshkumare: yes
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