Find the range and domain
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for real numbers √a is only defined if a ≥0
√9-x^{2} ≥0
squaring on both sides
(9- x^{2})≥0
so we get x=(-3,+3)
domain of the function is (-3,+3)
similarly we get range of the function(3,0)
√9-x^{2} ≥0
squaring on both sides
(9- x^{2})≥0
so we get x=(-3,+3)
domain of the function is (-3,+3)
similarly we get range of the function(3,0)
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