Find the range of ball which, when projected with a velocity of 29.4 m s ^- 1 just passes over a pole 4.9 m high
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Answer:
first by using height and velocity calculate sin theta of projectile
h=u²sin²theta/2g
4.9=29.4²sin²theta/2×10
sin²theta=0.113
theta=20
now,
R=u²sin2theta/g
R=29.4²×sin40/10
R=55.55m
Step-by-step explanation:
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