Find the range of f(x)= 3sinx + 4cosx - 5
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let f(x) = y
⇒y = 3sinx + 4cosx - 5
diving hole equation by 5 on both sides
⇒y/5 = 3sinx/5 + 4cosx/5 - 1
let 3/5 = cos k
so 4/5 = sin k
⇒y/5 = cosk.sinx + sink.cosx - 1
⇒y = 5(sin(x + k) - 1)
so we know
-1≤ sin(x+k) ≤1
⇒ -2≤ sin(x+k) - 1 ≤ 0
⇒ -10≤ 5[sin(x+k) -1]≤0
so the range of f(x)∈ [-10,0] ANSWER
⇒y = 3sinx + 4cosx - 5
diving hole equation by 5 on both sides
⇒y/5 = 3sinx/5 + 4cosx/5 - 1
let 3/5 = cos k
so 4/5 = sin k
⇒y/5 = cosk.sinx + sink.cosx - 1
⇒y = 5(sin(x + k) - 1)
so we know
-1≤ sin(x+k) ≤1
⇒ -2≤ sin(x+k) - 1 ≤ 0
⇒ -10≤ 5[sin(x+k) -1]≤0
so the range of f(x)∈ [-10,0] ANSWER
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1
Answer:
Mark as brainliest
This is a very conceptual question and has a couple of more methods of solving.
Step-by-step explanation:
You just have to use range of sinx and voila!
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