Find the range of f(x)=x^2+2x+3
Answers
Answered by
1
Answer:
f (x)=x^2+2x+3
f'(x)=2x+2
Answered by
1
f(x) = x² + 2x + 3
Answer:
f(x) = x²+2x+3 , then
f(0)=3
f(-1)=2
f (x)=x^2+2x+3
f'(x)=2x+2
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