Question

find the range of first 'n'natural number​

Answer 1

Step-by-step explanation:

 Range of the first 'n' natural numbers = n - 1. Range of the last n negative integers = -1-(-n)=n-1. Range of the first 'n' positive even integers = 2n - 2 .

Answer 2

$\huge\fbox\pink{❥ANSWER}$

Range of the first 'n' natural numbers = n - 1. Range of the last n negative integers = -1-(-n)=n-1. Range of the first 'n' positive even integers = 2n - 2 .

Step-by-step explanation:

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