Question

find the range of function f={(x,x^2/x^2+1)}​

Answer 1

Answer:

f(x)=

1+x

2

x

2

domain is R

let y=

1+x

2

x

2

⇒y+x

2

y=x

2

x

2

(y−1)+y=0

x

2

=

1−y

y

⇒x=±

1−y

y

, y



=1 & y≯1

so range is [0,1)