Math, asked by priya1039, 11 months ago

Find the range of the function f(x)=x^2+2x+1/x^2-8x+12

Answers

Answered by Anikvish842
0

Answer:


Step-by-step explanation:

The range of function is 6

so, x = 6

f(6)=(6)²+2x6+1/2-8x6+12

    = -4/8

    = -1/2

Answered by Anonymous
0

SOLUTION ⚜️

 given \: f(x) = \frac{ {x}^{2} + 2x + 1 }{ {x}^{2}  - 8x + 12}

Here, f(x) is an rational function of x as \frac{ {x}^{2} + 2x + 1 }{ {x}^{2}  - 8x + 12} is rational expression.

 \therefore f(x) \: assumes \: real \: values \: x \: espects  \\  for \: the \: values \: of \: x \: for \: which \:  {x}^{2}  - 8x + 12 = 0

i.e.,(x - 6)(x - 2) = 0 \rightarrow x = 6,2 \\  \therefore domain \: of \: f(x)

= R-{2,6}

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