Question

find the range of (x+y)², 2x²y² ,3/2(x²+2x),(y+4)²,2xy+x² where the given values are x=1 ,y=1

ans=23

Answer 1

✔️✔️Here the values are given as;
x=1 and y=1.


⭕️Substitute the values of x and y.


You'll get 4, 2, 9/2, 25, 3

⭕️simplify it further!

=4, 2, 2.5, 25, 3

✔️✔️We know that range is found by :-

Range =max. values - min. values .

⭕️max. value =25

⭕️min. value =2

»»substituting;

⭕️️therefore the range = 25-2

=23

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