Question

find the rate change of h^2/(m^2x^2+yxz)^2 w. r. t. x​

Answer 1

Step-by-step explanation:

☯ Let the age of son be x years.

Given that, man is twice as old as his son.

$:\implies\sf Man's \: age = 2x$

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$\underline{\bigstar\:\boldsymbol{As \: per \: given \: condition \::}}$

Twenty years ago, the age of the man was 12 times the age of the son.

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Therefore,

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$:\implies\sf 2x - 20 = 12(x - 20) \\\\\\:\implies\sf 2x - 20 = 12x - 240 \\\\\\:\implies\sf 12x - 2x = 240 - 20\\\\\\:\implies\sf 10x = 220\\\\\\:\implies\sf x = \cancel\dfrac{220}{10}\\\\\\:\implies{\underline{\boxed{\frak{\pink{x = 22}}}}}\:\bigstar$

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Hence,

Son's age = 22 years

Man's age = 2x = 2(22) = 44 years

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$\therefore\:{\underline{\sf{Hence, \ their \: present \ ages \ are \ \bf{22 \: years \: and \: 44 \: years}.}}}$