Math, asked by pompamandal982468953, 8 months ago

Find the rate of interest compounded annually if the compound interest on
10,000 is 1236 after 2 years.​

Answers

Answered by sahaniramkumar64
1

Answer:

rate=1236×100/10000×2=6.18

Answered by kaurkawaldeep377
1

Answer:

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Find the compound Interest on Rs. 10,000 at the rate of 18 percent per annum for 8 months when interest is compounded every 4 months?

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Rs. 2472

Rs. 2520

Rs. 2480

Rs. 1236

Answer (Detailed Solution Below)

Option 4 : Rs. 1236

Detailed Solution

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Given:

Principal = Rs. 10,000

Rate = 18% per annum

Time = 8 months

Formula used:

CI = Amount - Principal

A = P[1 + (R/n100)]nt

Where, CI = Compound Interest, A = Amount, P = Principal, R = Rate, t = time, n = Number of times compounded per year

Calculation:

Rate of interest (R) = 18% per annum

Time (t) = 8 months = 8/12 years

Compounded per year (n) = 12/4 = 3

As we know that

A = P[1 + (R/n100)]nt

⇒ 10,000 × [1 + (18/3 × 100)]3 × (8/12)

⇒ 10,000 × [1 + 6/100]2

⇒ 10,000 × (53/50) × (53/50)

⇒ Rs. 11,236

Now, CI = Amount - Principal

⇒ Rs. (11,236 - 10,000)

⇒ Rs. 1236

∴ The compound Interest is Rs. 1236

Step-by-step explanation:

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