Question

Find the rate of interest compounded per annum for 3 years so that 4000 becomes

4635.50​

Answer 1

Answer:

Abe salle,abe salle

Ste valage p-by-step explanation:abe saller is correct answer

Answer 2

Let A=4635.50

P=4000

n=3

r=?

using A=p(1+r)^n

4635.50=4000(1+r)^3

=4635.50/4000=(1+r)^3

=1.158=(1+r)^3

=(1.158)^1/3=1+r

=1.05=1+r

=r/100=0.05

r=5%