Math, asked by pujasrivastav1991, 4 months ago

Find the rate of interest ; if S.I = Rs. 810 ; Principal = Rs. 4500 ; Time = 3 Year 4 Month​

Answers

Answered by akeertana503
4

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S. I = 810

P =4500

T =3 year 4month

R =100*S.I / P×T

R = 5.42%

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Answered by tusharraj77123
6

Answer:

Rate = 5.42 % (approx)

Step-by-step explanation:

Given :

Simple interest = ₹810

Principal = ₹4500

Time = 3 year 4 month or 3.32 years

To find :

The rate

Taken :

To find the rate use this formula -:

\boxed{\tt{R=\dfrac{S.I.\times100}{P\times T}}}

Where,

R = Rate

S.I. = Simple interest

P = Principal

T = Time

Solution :

:\implies\tt{R=\cancel{\dfrac{810\times100}{4500\times3.32}}}

:\implies\tt{R=\cancel{\dfrac{243.97}{45}}}

:\implies\tt{R=5.42\%(approx)}

So , the rate of interest is 5.42% (approx) ..


pujasrivastav1991: Thank u
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