find the ratio between the area of triangle ABC with sides 20, 20 and 10 and triangle DEF with sides 60, 60 and 30?
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area(ABC)/area(DEF)=(AB/DE)^2=(BC/EF)^2=(AC/DF)^2
=(20/60)^2=(20/60)^2=(10/30)^2
=(1/3)^2
=1/9
RATIO=1:9
PLEASE MARK AS THE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
=(20/60)^2=(20/60)^2=(10/30)^2
=(1/3)^2
=1/9
RATIO=1:9
PLEASE MARK AS THE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
AkanshaMehra:
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