Find the ratio by mass of combining elements in i) Magnesium oxide and ii) Hydrogen sulphide. [ Given Atomic mass of magnesium = 24u, oxygen = 16u, sulphur = 32u, hydrogen = 1u]
Answers
Answered by
24
HI BRO HERE IS YOUR ANSWER
The Ratio by mass of magnesium oxide (MgO):
the atomic mass of magnesium is 24u and for Oxygen is 16u ( which is already given)
Mass percentage of Magnesium:
24/(24+16)*100
= 24/40*100
60%
mass percentage of Oxygen:
16/40*100
= 40%
Similarly,
for Hydrogen Sulphide (H2S):
Given: Sulphur atomic mass = 32u and for Hydrogen it is 1u.
Mass percentage of sulphur:
32/(32+1+1) * 100
= 94.11%
mass percentage of Hydrogen:
(1+1)/(32+1+1)*100
= 5.88%
LIKES TO HELP
HOPE IT HELP
BY GLADIATOR
Answered by
4
Answer:
PLS REFRAIN FROM COPYING ANSWERS AND WRITIN THEM IN ASSIGNMENTS
Find the ratio by mass of combining elements in i) Magnesium oxide and ii) Hydrogen sulphide. [ Given Atomic mass of magnesium = 24u, oxygen = 16u, sulphur = 32u, hydrogen = 1u]
Similar questions