Question

find the ratio in which line segment joining the point (2,3)and (3,-2)​ is divided by x axis

Answer 1

Answer:

Step-by-step explanation:

Let the point on $x$ axis is Q $(x,0)$ since the $y$ coordinate is always zero on $x$ axis.

The given line segment joining A$(2,3)$ and  B$(3,-2)$.

Let Q divide the line segment joining the points $(2,-3)$ and $(4,6)$ in the ratio $m:1$.

The coordinates of

Q=$Q=(mx2+x1/m+1,my2+y1/m+1)</p><p>(x,0)=3m+2/m+1,-2m+3/m+1$

When we compare both sides

$-2m+3/m+1=0$

Find the value of $m$

$m=3/2$

Thus,the x-axis divide the line segment joining the points in the ratio of $1:2$ internally.