find the ratio in which P(4,m) divide the line segment joining the point A(2,3) and B(6,-3) Hence find m
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ratio is 1:1 and m is 0
Arnav582002:
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Hola there...
Let
P(4, m) = (x, y)
A(2, 3) = (x1, y1)
B(6, -3) = (x2, y2)
By using section formula in this points, we get.
Let the ratio in which P divide the line segment A and B be = k:1
Therefore,
x = kx2 + x1(1)/k + 1
=> 4 = 6k + 2 /k + 1
=> 4k + 4 = 6k + 2
=> 2k = 2
=.> k = 1
So, the ratio = 1:1
Now,
y = k(y2) + 1(y1) / k + 1
=> m = -3 + 3 /1 + 1
=> m = 0/2
=> m = 0. ...Ans
Hope this helps....:)
Let
P(4, m) = (x, y)
A(2, 3) = (x1, y1)
B(6, -3) = (x2, y2)
By using section formula in this points, we get.
Let the ratio in which P divide the line segment A and B be = k:1
Therefore,
x = kx2 + x1(1)/k + 1
=> 4 = 6k + 2 /k + 1
=> 4k + 4 = 6k + 2
=> 2k = 2
=.> k = 1
So, the ratio = 1:1
Now,
y = k(y2) + 1(y1) / k + 1
=> m = -3 + 3 /1 + 1
=> m = 0/2
=> m = 0. ...Ans
Hope this helps....:)
!!!
:)
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