find the ratio in which the line joining the points (6,3) and(3,-5) is divided by the x axis
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The answer is not 3:5 it is 1:3
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Answer:
let the ratio be k:1
if line joining the point (x1,y1) and the point(x2,y2) is divided by x axis (where y=0) in ratio k:1,
[ given, (x1,y1) = 6,3 and (x2,y2) = 3,-5 ]
Then y = 0 = (k.y2 + y1) / (k+1)
(-5k + 3)/(k+1) = 0
k = 3/5
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