Question

Find the ratio in which the line segment joining (-2, -3) and (5,6) is divided by (i) x-axis
(ii) y-axis. Also, find the coordinates of the point of ​

Answer 1

Answer:

Step-by-step explanation:

m = (6 + 3) / (5 + 2) = 9/7

Equation of line passing through (-2, -3) and (5, 6) is

y - 6 = (9/7)(x - 5) ===> y = (9/7)x - 3/7

(i). x-axis divides the line segment in ratio 3:1 at point (1/3, 0)

(ii). y-axis divides the line segment in ratio 8:3 at point (0, -3/7)

Answer 2

We know that

x = M1x2 +M2x1/M1+ M2

And

y = M1y2 + M2y1/M1 +M2

But we know that y=0

So

0 =6M1-3M2/M1 + M2

0 = 6M1 -3M2

-6M1 = -3M2

M1/M2 = 1/2

The ratio is 1 : 2

x = 1*5 +2*2/1+3 = 5+4 /3 =9/3 =3 The coordinate is (3,0)