. Find the ratio in which the line segment joining A (1, -5) and B (-4, 5) is divided by
the x – axis. Also, find the coordinates of the point of division
Answers
Answer:
Explanation:
Given :
- Points are A(1 , -5) & B(-4 , 5).
To Find :
- Ratio of line segment which is divided by x - axis & coordinates of the point of division.
Solution :
According to the question,
The line segment joining A(1, -5) and B(-4, 5) is divided by the x – axis.
.°. y - axis is 0.
We need to find "Ratio of line segment which is divided by x - axis", So ;
Apply section formula,
y = my2 + ny1/m + n
=> 0 = m × 5 + n × -5/m + n
=> 0(m + n) = 5m - 5n
=> 0 = 5m - 5n
=> 5m = 5n
=> m : n = 1 : 1
Now,
We need to "coordinate of the point of division", So ;
Apply section formula,
x = mx2 + nx1/m + n & y = my2 + ny1/ m + n
=> x = 1 × -4 + 1 × 1/1 + 1 & y = 1 × 5 + 1 × -5/1 + 1
=> x = -4 + 1/2 & y = 5 - 5/2
=> x = -3/2 & y = 0/2
=> x = -3/2 & y = 0
.°. (x, y) = (-3/2 , 0)
Hence :
Ratio of line segment which is divided by x - axis and coordinates of the point of division is 1 : 1 and (-3/2 , 0) respectively.
Points that are given= A(1, -5) & B(-4, 5).
Find the ratio in which the line segment joining the points is divided by the x - axis & also find the coordinates of the point of division.
The line segment joining the points is divided by the x - axis,
Therefore, y - axis is 0.
The Ratio in which the line segment is divided by the x - axis,
Applying Section Formula,
The coordinates of the point of division,
Applying Section Formula,
x = m × 2 + n × 1/m + n and y = my2 + ny1/n + n
→ x = 1 × - 4 + 1 × 1/1 + 1 and y = 1 × 5 + 1 × -5/1 + 1
→ x = -4 + 1/2 and y = 5 - 5/2
→ x = -3/2 and y = 0/2
→ x = -3/2 and y = 0