Question

find the ratio in which the line segment joining the points (-3,10) and (6,-8) is divided by (-1,6).​
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Answer 1

Answer:

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Answer 2

The point which divides the line segment joining (x1,y1) and (x2,y2) in the ratio m:n is given by ,

$x = \frac{mx2 + nx1}{m + n}$

$y = \frac{my2 + ny1}{m + n}$

Here, x = -1, y = 6

And the ratio m: n should be found out . So, we can take m/n as k.

So, the formula will become,

$x = \frac{kx2 + x1}{k + 1}$

$y = \frac{ky2 + y1}{k + 1}$

That is,

$- 1 = \frac{6k - 3}{k + 1}$

$- k - 1 = 6k - 3$

7k = 2

k = 2/7

That is,

m:n = 2:7 (Ans)

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