Question

find the ratio in which the line segment joining the points (-3,10) and (6,-8) is divided by (-1,6)​

Answer 1

Answer:

the ratio in which the line segment joining the points (-3,10) and (6,-8) is divided by (-1,6) is 2:7

Answer 2

Given ,

A point (-1,6) divide the line segment joining the points (-3,10) and (6,-8)

We know that , the section formula is given by

$\large \sf \fbox{(x,y) = \frac{m x_{2} +nx_{1} }{m + n} ,\frac{m y_{2} +ny_{1} }{m + n} }$

Thus ,

$</p><p> \sf \Rightarrow </p><p>- 1 = \frac{6m - 3n}{m + n} \\ \\ </p><p> \sf \Rightarrow </p><p> - m - n = 6m - 3n \\ \\</p><p> \sf \Rightarrow </p><p>2n = 7m \\ \\ </p><p> \sf \Rightarrow </p><p> \frac{m}{n} = \frac{2}{7}$

$\therefore{ \sf \bold{ \underline{The \: ratio \: is \: 2 : 7 }}}$