Question

Find the ratio in which the line segment joining the points (-3, 10) and (6,-8)is divided by (-1,6)​.

Answer 1

Diagram: P(-1,6)

______|_______

A(-3,10). B(6,-8)

Step-by-step explanation:

Let us name the point which divides the line segment as 'p'.

To find the ratio of the line segment, let us use section formula.

section formula=m1x2+m2x1 , m1y2+m2y1

m1+m2. m1+m2

A=(-3,10), B=(6,-8). {given}

• In this :
• X1= -3
• X2=10

• y1=6
• y2= -8

P=(m1)(x2) +(m2)(X1). ,. (m1)(y2) +(m2)(y1)

m1+m2. m1+m2

= (m1)(6) + (m2)(-3). , (m1)(-8)+(m2)(10)

m1+m2. m1+m2

= 6m1-3m2. ,. -8m1+10m2

m1+m2. m1+m2

Therefore;. -1= 6m1-3m2

m1+m2

= -m1-m2=6m1-3m2

= 3m2-m2=6m1+m1

=2m2=7m1

=m1 = 7

m2. 2

Therefore, m1:m2 = 7:2.

I hope that this will help you.