Find the ratio in which the line segment joining the points A(5.-6) and
B(-1, 4) is divided by y-axis?
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0
Answer:
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Answered by
1
Answer:
ANSWER
Using the section formula, if a point (x,y) divides the line joining the points (x
1
,y
1
) and (x
2
,y
2
) in the ratio m:n, then
(x,y)=(
m+n
mx
2
+nx
1
,
m+n
my
2
+ny
1
)
Let the required ratio be m:n
here,x
1
=5,x
2
=−1,y
1
=−6,y
2
=−4
Then, According to question, we have ;
m+n
mx
2
+mx
1
=0
⇒m(−1)+n(5)=0
⇒5n=m
⇒m=5n
⇒
n
m
=
1
5
⇒m:n=5:1
Coordinate of the point of division
=(0,
m+n
my
2
+my
1
)
=(0,
6
5(−4)+1(−6)
)
=(0,
6
−20−6
)
=(0,
3
−13
)
Step-by-step explanation:
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