Question

find the ratio in which the line x-y-2=0divides the line segment joining points (3, -1) and (8, 9) ​

Answer 1

Answer:

ratio is 2/3

Step-by-step explanation:

Let the ratio be m:n

Here, x  

1

​  

=3,y  

1

​  

=−1,x  

2

​  

=8,y  

2

​  

=9

(  

m+n

mx  

2

​  

+nx  

1

​  

 

​  

,  

m+n

my  

2

​  

+ny  

1

​  

 

​  

)

(  

m+n

8m+3n

​  

,  

m+n

9m−n

​  

)

Given straight line is x−y−2=0

⇒  

m+n

8m+3n

​  

−  

m+n

9m−n

​  

−2=0

⇒8m+3n−9m+n−2m−2n=0

⇒−3m+2n=0

3m=2n⇒  

n

m

​  

=  

3

2

​  

⇒m:n=2:3 internally.