find the ratio in which the points P (3, 4) divide line joining of the point A (1,2) B (6,7)
by using m1 and m2 = k+1
plz help!
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let point p(3,4) divides the line segment in the ratio k:1
therefor
p(3,4)=(k×6+1×1÷k+1,k×7+1×2÷k+1)
(3,4)=(6k+1÷k+1,7k+2÷k+1)
3=6k+1÷k+1
3(k+1)=6k+1
3k+3=6k+1
3-1=6k-3k
2=3k
k=3/2
therefore the ratio is
(2/3,1)
therefor
p(3,4)=(k×6+1×1÷k+1,k×7+1×2÷k+1)
(3,4)=(6k+1÷k+1,7k+2÷k+1)
3=6k+1÷k+1
3(k+1)=6k+1
3k+3=6k+1
3-1=6k-3k
2=3k
k=3/2
therefore the ratio is
(2/3,1)
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