Question

find the ratio in which the straight
dine
2x + 3y -5=0 divides
joining the points
the points (0,0) and (-2,1).
the
line​

Answer 1

Answer:

Let P(p,-1) divide the line segment

joining the points A(1,-3)and B(6,2)

in m : 1

then using section formula

P=

m+1

6m+1

−−−(1) and −1=

m+1

2m−3

−−−(2)

Form equation (2) -m-1=2m-3

3m=2

[m=

3

2

]

Hence P divide line segment in 2:3.

now form eq (1)

p=

m+1

6m+1

=

3

2

+1

6×

3

2

+1

=

3

5

3

15

=3.

Hence value of P in 3.