Question

find the ratio in which the straight line3x-4y=7
divides the join of (2, -7) and
Straight line
32-uy=7
(-1, 3).​

Answer 1

Step-by-step explanation:

Equation of the line is 3x - 4y= 7

Given point are A(2,-7) and B(-1,3).

The ratio in which the line L=0 divides the

line join of point A and B is L11/L22=

$\frac{(ax1 + by1 + c}{(ax2 + by2 + c}$

$= \frac{[3.2-4(-7)-7}{[3-(-1)-4.3-7} = \frac{(6+28-27)}{-3-12-7}$

$= \frac{-27}{-22} = \frac{27}{22}$

The ratio is positive, therefore given points lie on opposite sides of the line.

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