Find the ratio in which the y axis divides the lone segment joining the points (-4,-6)and (10,12).also find the coordinate of the point of division
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let the coordinates of the point be (0,y) and y-axis divides the line segment in the ratio k :1.
(0,y) = {(10k-4)/k+1 ,(12k-6)/k+1}
0=10k-4/k+1
10k =4
k=2/5 ==>the ratio of division is 2:5
now, y =(12k-6)/k+1
y={(12*2/5) -6}/(2/5)+1
y =-6/7
thus the coordinates of the point is (0,-6/7)
hope it helps...
(0,y) = {(10k-4)/k+1 ,(12k-6)/k+1}
0=10k-4/k+1
10k =4
k=2/5 ==>the ratio of division is 2:5
now, y =(12k-6)/k+1
y={(12*2/5) -6}/(2/5)+1
y =-6/7
thus the coordinates of the point is (0,-6/7)
hope it helps...
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