Question

find the ratio in which x-5y+15 =0 divides the line segment joining the points (2,1) and (-3,6).​

Answer 1

Answer:

use formula

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

let the ratio be k:1

then using the formula

[k×(-3)+1×2/k+1 ,k×6+1×1/k+1]

[-3k+2/k+1,6k+1/k+1]

putting those values instead of x and y in the given equation, we will get:-

-3k+2/k+1 - 5(6k+1/k+1) + 15=0

-3k+2/k+1 - 30k+5/k+1 + 15=0

-3k+2-30k-5+15k+15/k+1=0

-18k+12=0

k=12/18=6/9=3/2

HENCE THE RATIO IN WHICH THE LINE IS DIVIDED IS 3:2.

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