Question

Given A = 2i – 2j + K the magnitude of this vector is?​

Answer 1

Answer:

The magnitude of the given vector is,

A =

=

$\sqrt{} (2 {}^{2} + 2 {}^{2} + 1 {}^{2} )$

=

$\sqrt{} (4 + 4 + 1)$

=

$\sqrt{9}$

= 3

Hope this helps you....

Answer 2

Given : Vector A = 2i - 2j + k

To find : The magnitude of vector A

Solution :

The magnitude of vector A = 3 units

We can simply solve this numerical problem by using the following process. (our goal is to calculate the magnitude of the vector A)

Here, the magnitude of the given vector will be calculated in the general method.

If, Vector P = ai + bj + ck

Then |P| = √✓(a)²+(b)²+(c)²]

Similarly,

Vector A = 2i - 2j + k

Or, Vector A = 2i - 2j + 1k

Magnitude of vector A :

|A| = √(2)²+(-2)²+(1)² = √(4+4+1) = √9 = 3 units

(This will be considered as the final result.)

Hence, the magnitude of vector is 3 units.