Question

Find the ratio in which y-axis divides the line segment joining the points A(5.-6) and
B(-1.-4). Also find the coordinates of the point of division​

Answer 1

Answer:

The ratio in which y axis divide the line segment is - x1:x2=

= - 5 : -1

= 5:1

Answer 2

(x1, y1) = (5, -6)

(x2, y2) = (-1,-4)

Let (0, y) be the coordinates of the point on y axis that divides line segment AB in the ratio m:n. (On Y axis, x coordinate is zero)

Using section formula,

(0, y) = mx2 + nx1 , my2 + ny1

(m + n) (m + n)

0 = m(-1) + n(5)

m + n

0(m + n) = -m + 5n

0 = 5n - m

m = 5n

m/n = 5/1 (equation 1)

Therefore, the ratio in which y axis divides AB is 5:1

Now,

y = m(-4) + n(-6)

m + n

= -4m -6n

m + n

= -4(5) -6(1) (from equation 1)

5 + 1

= -20 -6

6

= -26/6 = -13/3

Hence the coordinates of the point that divides AB is (0, -13/3)

Hope it helps!!! :)