Question

Find the ratio in which y - axis divides the line segment joining Points (5,-6) and (-1,-4) also find point of intersection

Answer 1

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Answer 2

Let the y-axis divides the line segment joining points (5,-6) and (-1,-4) in ratio k:1 and point of intersection (0,y)

Using Section formula,
$( \frac{ - 1k + 5}{k + 1} coma \frac{ - 4k + ( - 6)}{k + 1} ) = (0 \: coma \: y)$
(-k+5)/(k+1) = 0
-k+5 =0
k = 5
Hence the y-axis divides the line segment joining points (5,-6) and (-1,-4) in ratio 5:1

Since y = (-4k-6)/(k+1)
y = (-20-6)/(5+1)
y = -26/6
y = -13/3
Hence point of intersection is (0, -13/3)
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