Find the ratio of acceleration of body 1 to body 2 if the mass of body 1 is thrice of body 2 and the force applied on body 1 is twice of force applied on body 2
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Answers
(a) Started business with cash 10
(b) Paid commission in advance 300
(c) Purchased goods for cash 15,000 and on credit '12,000
(d) Sold goods for cash 8,000 costing 4,0
(e) Paid rent 450 and rent outstanding being 100
(1) Bought motorcycle for personal use 3000
Answer: (1) Velocity or speed (v) m/s [M0L1Tñ1]
(2) Acceleration (a) m/s2 [M0LTñ2]
(3) Momentum (P) kg.m/s [M1L1Tñ1]
(4) Impulse (I) Newton sec or [M1L1Tñ1]
kg. m/s
(5) Force (F) Newton [M1L1Tñ2]
(6) Pressure (P) Pascal [M1Lñ1Tñ2]
(7) Kinetic energy (Ek) Joule [M1
L2
Tñ2]
(8) Power (P) Watt or Joule/s [M1L2Tñ3]
(9) Density (d) kg/m3 [M1Lñ3T0]
(10) Angular displacement () Radian (rad.) [M0L0T0]
(11) Angular velocity () Radian/sec [M0L0Tñ1]
(12) Angular Acceleration () Radian/sec2 [M0L0Tñ2]
(13) Moment of inertia (I) kg.m2 [ML2T0]
(14) Torque () Newton-meter [ML2T-2]
(15) Angular momentum (L) Joule sec [ML2Tñ1]
(16) Force constant or spring constant (k) Newton/m [M1L0Tñ2]
(17) Gravitational constant (G) Nñm2/kg2 [Mñ1L3Tñ2]
Explanation:1 Iy = 9.46 × 1015 m
1 m = = 1.057 × 10ñ16 Iy
37. P = 2 (l + b) ± 2 (l + b)
= 2(10.5 + 5.2) ± 2(0.2 + 0.1)
= (31.4 ± 0.6) cm.
38. (i) Mass of box = 2.3 kg
Mass of gold pieces = 20.15 + 20.17 = 40.32 g = 0.04032 kg.
Total mass = 2.3 + 0.04032 = 2.34032 kg
(1) Distance : It is the actual path length covered by a moving particle in a
given interval of time.
(i) Its a scalar quantity.
(ii) Dimension : [M0 L1 T0]
(iii) Unit : metre (S. I.)
(2) Displacement : Displacement is the change in position vector i.e., A
vector joining initial to Æ nal position.
(i) Displacement is a vector quantity
(ii) Dimension : [M0
L1 T0]
(iii) Unit : metre (S. I.)
(iv) If are the displacements of a body then the total (net)
displacement is the vector sum of the individuals.
(3) Comparison between distance and displacement :
(i) Distance > 1, Displacement 1.
(ii) For a moving particle distance can never be negative or zero while
displacement can be i.e., Distance > 0 but Displacement > = or < 0
(iii) For motion between two points displacement is single valued while
distance depends on actual path and so can have many values.
(iv) For a moving particle distance can never decrease with time while
displacement can. Decrease in displacement with time means body
is moving towards the initial position.
(v) In general magnitude of displacement is not equal to distance.
However, it can be so if the motion is along a straight line without
change in direction.When only direction When only magnitude When both magnitude and
of velocity changes of velocity changes direction of velocity changes
Acceleration Acceleration parallel or Acceleration has two components
perpendicular to velocity anti-parallel to velocity one is perpendicular to velocity
and another parallel or antiparallel
to velocity
e.g. Uniform circular e.g. Motion under e.g. Projectile motion
motion gravity
(3) Dimension : [M0 L1
Tñ2]
(4) Unit : metre/second2 (S. I.); cm/second2 (C. G. S.)
(5) Types of acceleration :
(i) Uniform acceleration : A body is said to have uniform acceleration
if magnitude and direction of the acceleration remains constant during
particle motion.
If a particle is moving with uniform acceleration, this does not
necessarily imply that particles is moving in straight line, e.g.,
Projectile motion.
(ii) Non-uniform acceleration : A body is said to have non-uniform
acceleration, if magnitude or direction or both, change during motion.
(iii) Average acceleration : = =
The direction of average acceleration vector is the direction of the
change in velocity vector as =
(iv) Instantaneous acceleration = = =
(v) For a moving body there is no relation between the direction of
instantaneous velocity and direction of acceleration.
e.g.(a) In uniform circular motion = 90° always (b) in a projectile
motion is variable for every point of trajectory.
just read this all u will get ur answer -