Find the ratio of Minimum to Maximum wavelength of radiation emitted by electron in ground state of Bohr's hydrogen atom. Please write the steps too!!
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Answered by
0
Answer:
λ
1
=R
new
(
n
1
2
1
−
n
2
2
1
)
Where,
Rydberg Constant,R=
8ε
o
2
h
3
c
me
4
λ
min
λ
max
=
R(
1
2
1
−
∞
1
)
R(
1
2
1
−
2
2
1
)
=
4
3
Hence, the ratio of minimum to maximum wavelength of radiation emitted is
4
3
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Explanation:
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