Find the ratio of the boundaries of a circular field of radius 50m and of a square field of side 22 m
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ratio of
( boundaries of a circular field):(square field)
= 22/7 × 50×2 ÷ ( 4×22)
= 22/7 × 50/22× 2 /4
= 25/7
=> ( boundaries of a circular field):(square field)
= 25:7
( boundaries of a circular field):(square field)
= 22/7 × 50×2 ÷ ( 4×22)
= 22/7 × 50/22× 2 /4
= 25/7
=> ( boundaries of a circular field):(square field)
= 25:7
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