find the ratio of the gravity of earth to the gravity at moon
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The ratio would be in the attachment.
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0gaurav0:
Bro, your solution is wrong as you have given a wrong formula to calculate g. g=GM/r² not GM/r please correct the mistake you have committed. A lot of love and peace ✌️
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The formula to find the acceleration due to gravity of any planet is:-
g=GM/r²
= G•ρ•V/r² [since, M = ρ × V ; where ρ = density & V = volume]
= G•ρ•4/3 π r³/r² [since volume of a sphere = 4/3*π r³]
=4/3π*G*ρ*r
Similarly,
ge = 4/3π*G*de*De/2
And,
gm=4/3π*G*dm*Dm/2
Now,
ge/gm=(de•De)/(dm•De)
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Regards,
Gaurav kumar
g=GM/r²
= G•ρ•V/r² [since, M = ρ × V ; where ρ = density & V = volume]
= G•ρ•4/3 π r³/r² [since volume of a sphere = 4/3*π r³]
=4/3π*G*ρ*r
Similarly,
ge = 4/3π*G*de*De/2
And,
gm=4/3π*G*dm*Dm/2
Now,
ge/gm=(de•De)/(dm•De)
Please mark this solution as a brainliest answer and also follow me for more such detailed solutions in maths and physics.
Regards,
Gaurav kumar
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