find the ratio of the number of atom present in 16 gm o2 and 32 gm o3
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Explanation:
Option ( 4 ).
No. (Number) of atoms = x moles
Avogadro's number = x atomicity
Moles of O2 = 16/32
= 1/2
Moles of O3 = 32/48
=2/3
No. of atom of O2/ No. of atom of O3
=( 1/2 x Na x 2)/(2/3 x Na x 3)
Therefore, Ratio = 1:2.
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