Question

Find the ratio of the potential diff that must be applied across the parallel and series combination with 2 capacitors with thier capacitance 1:2 so energy stored in the 2 cases be the same

Answer 1

Explanation:

given

1.capacitance ratio =1:2

let c1=1k,c2=2; where I is constant

2. energy should be same in both cases

E in parallel =E in series

1/2 Cp.vp^2=1/2Cs.vp^2

Cp=

1/c=1/c1+1/c2

c=c1.c2/(c1+c2)

Cp=1.2k^2/3k

Cp=2k/3

Cs

c=c1+c2

Cs=3k

Cp.vp^2=Cs.vs^2

2k/3.vp^2=3k.vs^2

vp^2/vs^2=9/2

vp/vs=under root (9/2)

vp/vs=3/√2

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