Question

Find the ratio of the pressed exerted by a block of 400N when placed on a table top along its two different sides with dimension 20cm×10cm and 10cm×15cm​

Answer 1

Area(A) = 20 cm × 10cm

Force = 400N

$p = f \div a$

= 400/200 = 2 p(pascal) = 2

In second side

Area = 10cm × 15 cm

Force = 400N

= 400/150 = 2.667

Pressure exerted by a block = 2 + 2.667 = 4.667