Find the rationalising factor of 1 +√2+√3
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sorry but there is an invisible energy
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The rationalizing factor for (1+√2+√3) is (2+√2–√6): product = 4
(i)trial factor : (1+√2+√3)(1+√2–√3)↙=3+2√2–3=2√2
(ii) revised factor : √2(1+√2–√3)↙
(iii) improved factor : (2+√2–√6)
(iii)testing it out :
(1+√2+√3)(2+√2-√6)
=2+√2–√6
+2+2√2–2√3
+2√3+√6–3√2
=4→it works !
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