Math, asked by masterkavishbhatia, 1 year ago

find the real number X and Y gives that x-y=3/2 and x power 4+ y power four= 2657/16​

Answers

Answered by kingofself
4

Answer:

The real number of X and Y is 161 and 6 respectively.

Step-by-step explanation:

Given:

Find the real number X and Y gives that x-y=\frac{3}{2} and x power 4+ y power four= \frac{2657}{16}

Solution:

x – y = \frac{3}{2}, adding power to the 4 on both sides,  

(x - y)^4  = (\frac{3}{2})^4

X^4 + y^4 - 4x^3y + 6x^2y^2 - 4xy^3 = \frac{81}{16}

\frac{2657}{16} - 4x^3y + 2x y^2 (x - y) = \frac{81}{16}

\frac{2657}{16} - 4x^3y + 2x y^2 \times \frac{3}{2} = \frac{81}{16}

\frac{2657}{16} + 3xy^2 - 4x^3y = \frac{81}{16}

161 = 4xy (x  – y)

161 = 4xy (\frac{3}{2})

161 = 6xy

\frac{161}{6} = xy

Result:

The real number of X and Y is 161 and 6 respectively.

Learn more about above related problems:

Q: Real number x,y satisfy x^2+y^2=1. If the maximum and the minimum value of the expression z=4-y/7-x are m and m respectively, then find the value of (2m+6m)

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Q: Lcm of two prime number x and y (x>y) is 161 then the value of 3y-x is

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