Question

find the real numbers x such that x+3, 2x+5 and 3x +2 are the sides of a right angled triangle ​

Answer 1

Answer:

We have, 3 side of triangle

(x+1),(2x+5),(3x+2)

Therefore, (2+5)

2

=(3x+2)

2

+(x+1)

2

⇒4x

2

+25+20x=9x

2

+4+12x+x

2

+1+2x

4x

2

+25+20x=10x

2

+14x+5

6x

2

−6x−20=0

3x

2

−3x−10=0

x=+3±

6

9−4×3×(−10)

x=

6

3±

9+120

x=

6

3±

129

Hence, 2 values of x.

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Answer 2

Answer:

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