Math, asked by rp885464172, 9 months ago

find the real root:3root2 X^2 - 5 X -root 2 =0​

Answers

Answered by Cosmique
3

Answer:

3√2x^2 - 5x - √2 = 0

3√2x^2 -x(6-1) - √2=0

3√2x^2 - 6x + x - √2=0

3√2x ( x-√2) +1(x-√2) = 0

(3√2x+1) (x-√2)=0

x= -1/(3√2)

OR

x= √2

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