find the real root:3root2 X^2 - 5 X -root 2 =0
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3√2x^2 - 5x - √2 = 0
3√2x^2 -x(6-1) - √2=0
3√2x^2 - 6x + x - √2=0
3√2x ( x-√2) +1(x-√2) = 0
(3√2x+1) (x-√2)=0
x= -1/(3√2)
OR
x= √2
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