Question

Find the reaminder when x^ + 3x^2 + 3x is divided by 1-3x

Answer 1

Answer:

37/27 will be the remainder

Step-by-step explanation:

p(x)=x^3 + 3x^2 + 3x=x(x²+3x+3)

g(x)= -3x+1

∴3x=1 or x=1/3

Let us use Remainder theorem for this equation x(x²+3x+3)

p(1/3)=(1/3)[(1/3)²+3(1/3)+3]

=(1/3)[1/9+1+3]

=(1/3)(1+36)/9

=37/27