Question

find the reciprocal of root7 - root 6​

Answer 1

Answer:

$\sqrt{7} + \sqrt{6}$

Step-by-step explanation:

$\frac{1}{\sqrt{7} - \sqrt{6}}= \frac{1}{\sqrt{7} - \sqrt{6}} * \frac{\sqrt{7} + \sqrt{6}}{\sqrt{7} + \sqrt{6}}$

Using (a+b)*(a-b) = a^2 - b^2

= $\frac{\sqrt{7} + \sqrt{6} }{7-6} = \sqrt{7} + \sqrt{6}$

:)

Answer 2

  1/$\sqrt{7} - \sqrt{6}$

= 1 × $\sqrt{7} + \sqrt{6}$ ÷ $\sqrt{7} - \sqrt{6}$ × $\sqrt{7} + \sqrt{6}$

=$\sqrt{7} + \sqrt{6}$ ÷ √7²-√6²

=√7+√6 ÷ 7-6

= √7+√6 ÷ 1

=√7+√6