Question

find the rectangle having breadth 8 unit and diognal 17 units​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Breadth (b) = 8

Diagonal (d) = 17

Length ( l) = ?

by Pythagoras theorem

${d}^{2} = {l}^{2} + {b }^{2} \: \\ {l}^{2} = {d}^{2} - {b}^{2} \\ {l}^{2} = {17}^{2} - {8}^{2} = 289 - 64 \\ \\ {l}^{2} = 225 \\ \sqrt{l } = \sqrt{225} \\ l = 15$

Area =

$15 \times 8 = 120 \: sq \: unit$